0=-16t^2+56t+5

Solution for 0=-16t^2+56t+5 equation:

0=-16t^2+56t+5

We move all terms to the left:

0-(-16t^2+56t+5)=0

We add all the numbers together, and all the variables

-(-16t^2+56t+5)=0

We get rid of parentheses

16t^2-56t-5=0

a = 16; b = -56; c = -5;
Δ = b2-4ac
Δ = -562-4·16·(-5)
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-24\sqrt{6}}{2*16}=\frac{56-24\sqrt{6}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+24\sqrt{6}}{2*16}=\frac{56+24\sqrt{6}}{32}
$